## delta g

$\Delta G^{\circ}= \Delta H^{\circ} - T \Delta S^{\circ}$

$\Delta G^{\circ}= -RT\ln K$

$\Delta G^{\circ}= \sum \Delta G_{f}^{\circ}(products) - \sum \Delta G_{f}^{\circ}(reactants)$

705121606
Posts: 68
Joined: Wed Sep 18, 2019 12:17 am

### delta g

how do we know when we should use products-reactants vs delta g= delta h - t delta s

705121606
Posts: 68
Joined: Wed Sep 18, 2019 12:17 am

### Re: delta g

would it be the same as long as it is standard conditions? at standard temperature?

Posts: 116
Joined: Thu Jul 25, 2019 12:15 am

### Re: delta g

I think based on the information you are given. If it isn't as standard temp, use g= delta h - t delta s.

Jacob Motawakel
Posts: 103
Joined: Wed Sep 18, 2019 12:20 am
Been upvoted: 1 time

### Re: delta g

If we are given a chemical reaction formula and have the DeltaG values similar to that of the midterm, then we would use products minus reactants. However, if given entropy or enthalpy, I believe we would be prompted to use the DeltaG = DeltaH - TDeltaS.

Vinita Saxena 2I
Posts: 58
Joined: Fri Aug 09, 2019 12:16 am

### Re: delta g

It depends on what information you're given!

ShravanPatel2B
Posts: 100
Joined: Fri Aug 30, 2019 12:18 am

### Re: delta g

similar to the midterm problem when given the values for delta g you can you use the products minus reactants equation but when given values for enthalpy and entropy you should be prompted to use the second equation to solve for delta g.

WGaines_2E
Posts: 47
Joined: Mon Nov 18, 2019 12:18 am

### Re: delta g

depends on what is given. if you know dG for both then the easiest way is to simply use those values. If they aren't given you are probably going to have to use enthalpy, temp, and entropy to find the dG values then subtract reactants from products