Nernst Equation

[Philip]

Do we need to convert RT/nF * lnQ into 0.0592/n log Q?

Because I decided not to convert during one of the problems on the test as I forgot the conversion rate and I got the wrong answer even when I think my calculations were right. So is it necessary to use this conversion?

[Philip]

Also what R are we using?

[DanielTalebzadehShoushtari2A]

No, it is not necessary. Just make sure that the values you use for each variable are in the right units, and if they are not, convert them individually. T should be in Kelvin. R should be in the J/K form. F is the faraday constant in C/mol, and n is in mol. lnQ is unitless. Altogether, the term should come to be in units J/C, which is volts.

[Julia Holsinger_1A]

I convert RT/F to 0.025693 V and it has always given me the correct answer when I plug it in. I think you need to be careful of how you round if you are calculating RT/nF

[Lauren Tanaka 1A]

You don't need to convert but Dr. Lavelle said in lecture that the conversion can be useful in biological situations since it makes it easier to calculate pH.

[Indy Bui 1l]

No it is not necessary. Just make sure you plug in the correct values for R, F, and T. For R you should usually be using the 8.314J/K*mol.

[Ashley Alvarado 2C]

That conversion is useful when the system is at room temperature.