## k versus k prime

$\frac{d[R]}{dt}=-k[R]; \ln [R]=-kt + \ln [R]_{0}; t_{\frac{1}{2}}=\frac{0.693}{k}$

Sanjana Borle 2K
Posts: 111
Joined: Fri Aug 09, 2019 12:15 am

### k versus k prime

I dont conceptually understand the difference between k and k prime. Why does k eq equal k divided by k prime? Is it products over reactants?

MingdaH 3B
Posts: 133
Joined: Thu Jul 11, 2019 12:17 am

### Re: k versus k prime

k' is a constant generally used for the reverse reaction rate. It is similar to the concept of products over reactants, since the equation divides the rate at which products are formed over the rate at which reactants are formed.

Juliana Chopelas 1A
Posts: 50
Joined: Sat Aug 24, 2019 12:16 am

### Re: k versus k prime

K is the normal rate of a reaction while k prime is the reverse rate of a reaction

KSong_1J
Posts: 101
Joined: Thu Jul 11, 2019 12:17 am

### Re: k versus k prime

k is the rate constant for the forward reaction, while k prime is the rate constant for the reverse reaction

405268063
Posts: 102
Joined: Thu Jul 25, 2019 12:17 am

### Re: k versus k prime

Yes, like the previous responders have said, k prime generally refers to the reverse reaction rate and k refers to the forward reaction rate.

Kaylee Clarke 1G
Posts: 103
Joined: Fri Aug 30, 2019 12:15 am

### Re: k versus k prime

k prime refers to the reverse reaction while k refers to the forward reaction!

Natalie Benitez 1E
Posts: 100
Joined: Fri Aug 02, 2019 12:15 am

### Re: k versus k prime

Is k and k' related to each other since one is the rate of the forward reaction and the other is the rate of the reverse reaction?