QD3 Midterm

[305421980]

I know this question isn't about electrochemical, but the only acid and base section I could find was for 14A.
Somehow I got this question right on the midterm but don't know why or how.
It asks:
At pH 6 what is the net charge for acetic acid, CH3COOH (pKa=4.75)?

What is the concept behind this?

[MingdaH 3B]

Since pH is higher than the pKa, the acid will dissociate into its conjugate base and H+, and so its conjugate base will have a charge of -1.

[KnarGeghamyan1B]

Why would it be -1 exactly?

[jisulee1C]

At the pH of 6 you are assuming that the acetic acid dissolves into a higher concentration of it's conjugate base CHCH3COO- because the pKa (of acetic acid) =4.75 and the conjugate acid has a change of -1.

[205154661_Dis2J]

You are assuming that acetic acid dissolved into CHCH3COO- and H+ due to the pH of 6.

[005206171]

Acetic acid will lose its proton/H+ because it’s an acid. Its conjugate base is CH3COO which makes its charge -1