isochoric/isometric: $\Delta V = 0$
isothermal: $\Delta T = 0$
isobaric: $\Delta P = 0$

SubparChemist
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Joined: Fri Sep 25, 2015 3:00 am

Is the water bath within a calorimeter considered part of that system?

For question 8.23, it asks, "A calorimeter was calibrated with an electric heater, which supplied 22.5 kJ of energy as heat to the calorimeter and increased the temperature of the calorimeter and its water bath from 22.45 degrees Celsius to 23.97 degrees Celsius. What is the heat capacity of the calorimeter?"

Why is it that we did not need to solve for the amount of energy it took as heat to raise the temperature of the water and then subtract that value from the overall energy to see how much went into raising the temperature of the calorimeter? Do this mean that the water bath is considered to be a component of the calorimeter?

Chem_Mod
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### Re: 8.23 Question About Calorimeters

If the mass of water was not given, then you have no choice but to consider the calorimeter+water as a whole unit and find their combined heat capacity.