Sapling HW Bond Length

[KMcFarland_2L]

In the sapling homework, the solution has Si-S having a longer bond length than Si-O. I thought that since O has a larger atomic radius then the Si-O bond length would be longer. Why would Si-S have a longer bond length than Si-O?

[Navdha Sharma 3J]

I think you have interpreted the relationship between the atomic radius of O and S incorrectly. S has a larger atomic radius as atomic radii increases down the group.

[Michael Sun Dis 3G]

S has a larger atomic radius, as it has an extra electron shell. The Si-S bond is longer because of this difference in the atomic radii of S and O.

[Nathan Lao 2I]

The periodic trend for atomic radii is that it increases down a group! Since S is one period below O on the periodic table, it has a larger atomic radius and that's why the bond length would be larger.

[Shruti Kulkarni 2I]

Hi! S actually has a larger atomic radius as it has more electrons, which would make the bond length between Si-S longer than that of Si-O. Atomic radii increase down the period! And as S has a larger radius, it will have a longer bond length in comparison to O.

[Joel Meza 3I]

It is actually S that has a larger atomic radius than O. You might have confused the trend for atomic radii on the period table.

[Jason_John_2F]

s is below o on the periodic table meaning that the atomic radius is larger and therefore the bond length is larger

[Jonathan3B]

Larger atomic radius=longer bond length