Sapling #19
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Sapling #19
Is there an error with this problem, or am I missing something? This is an SO2 molecule, not H2S, right? Would the answer still be dipole-dipole or would it be London dispersion?
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Re: Sapling #19
I said dipole-dipole, because O is more electronegative than S and the partially positive (S) and partially negative (O) areas of each molecule are attracted to each other. Not sure why it says H2S or that H2S is polar (I think it meant to say SO2).
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Re: Sapling #19
Yea I agree with what is written above. The dipole-dipole interaction gives O a partial negative and S a partial positive charge. So because of that the interaction u see above is dipole dipole. Normally all polar molecules that are not ionic nor hydrogen bonds are dipole dipole
Re: Sapling #19
I just saw that Dr. Lavelle responded to another post about this and said that H2S was a mistake (meant to say SO2).
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Re: Sapling #19
Yes I think it should say SO2 instead of H2S. I said it was still dipole-dipole since the slightly positive S end of one molecule is attracted to the slightly negative O end of the other molecule.
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Re: Sapling #19
Had the same issue regarding this problem! I figured it was an error in the problem itself but I said it was dipole-dipole.
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