H2O VSEPR
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Re: H2O VSEPR
H2O would actually be bent shape because the two electron pairs from the oxygen will push the bonds between hydrogens down, giving it a bent shape.
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Re: H2O VSEPR
H20 would be bent because it has 2 lone pairs pushing down on the bonds between the oxygen and the hydrogen.
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Re: H2O VSEPR
Water would actually have a bent shape due to the two lone pairs of electrons present on the oxygen molecule, pushing the hydrogen atoms down further which results in a shift from a linear molecule to a bent molecule.
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Re: H2O VSEPR
Hey!
Although there are 4 bonding regions for H20, there are still 2 lone pairs. This makes the shape of the molecule bent since the two lone pairs are pushing the electrons from the two bonded atoms. Also, this would make the angles between the molecules less than 109.5. Hope this helps!
Although there are 4 bonding regions for H20, there are still 2 lone pairs. This makes the shape of the molecule bent since the two lone pairs are pushing the electrons from the two bonded atoms. Also, this would make the angles between the molecules less than 109.5. Hope this helps!
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Re: H2O VSEPR
Hi! It's important to differentiate between the arrangement of electron densities and the shape of a molecule.
H2O has 4 regions of electron densities. Therefore, it has tetrahedral arrangement of electron densities.
However, because 2 of them are lone pairs, the shape of the molecule is bent.
H2O has 4 regions of electron densities. Therefore, it has tetrahedral arrangement of electron densities.
However, because 2 of them are lone pairs, the shape of the molecule is bent.
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Re: H2O VSEPR
Remember when trying to figure out molecular shape, you only want to consider the amount of atoms present, not the amount of e- densities. So H20 has only two atoms branching from the central atom, making it bent with its lone pairs.
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Re: H2O VSEPR
Only the atoms matter so there's not enough to form either of those shapes you mentioned.
Re: H2O VSEPR
H20 would have a bent shape since there are 4 electron domains; 2 being lone pairs and the other two being bonds.
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Re: H2O VSEPR
The shape would be bent because there are the two hydrogens attached to the central oxygen atom, but there are 2 lone pairs of electrons also attached to the atom. Since the electron repulsion between two lone pairs is greater than the repulsion of two bonding pairs they will shift the two hydrogens bonded closer together to form a bent shape rather than a linear one.
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Re: H2O VSEPR
Becase H2O has 2 lone pairs, it has a AX2E generic formula. This is a bent shape.
Remember that A is the central Atom, X is the # of bonded atoms, and E is the # of lone pairs
This chart is very helpful in recognizing the shapes: https://www.templateroller.com/template ... chart.html
Remember that A is the central Atom, X is the # of bonded atoms, and E is the # of lone pairs
This chart is very helpful in recognizing the shapes: https://www.templateroller.com/template ... chart.html
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Re: H2O VSEPR
H20 has a bent shape due to the two lone pairs on the oxygen. Due to electron repulsion the hydrogens bonds would be pushed down.
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Re: H2O VSEPR
it would be bent
there are 4 total electron density regions, with two being lone pair electrons and 2 being bonds
there are 4 total electron density regions, with two being lone pair electrons and 2 being bonds
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Re: H2O VSEPR
A molecule with 4 regions of electron density, 2 lone pairs, and 2 bonding pairs, is bent. However, I believe that this could be characterized as having tetrahedral arrangement of electron density.
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Re: H2O VSEPR
Since there are three domains of electron density, one of which being a lone pair, the shape will be bent (or angular) since the lone pair pushes down on the hydrogens.
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Re: H2O VSEPR
H2O has a bent shape because it has two outer atoms (the two hydrogens that it bonds to) and two lone pairs (the 2 lone pairs from oxygens).
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Re: H2O VSEPR
The shape would be bent. Shape only looks at the position of bonds and not the position of lone pairs. Even though H2O only has two bonds, it is still sp3 because it has two bonds and two lone pairs, I think this may be why you thought it was tetrahedral.
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Re: H2O VSEPR
There's one central atom (A), two interactions occurring on account of the bonding with two hydrogen atoms (B2), and two lone pairs on the central atom (E2). Upon examining the molecule with the geometry of AB2E2, the descriptor is bent.
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Re: H2O VSEPR
Although there are 4 bonding regions for H20, there are still 2 lone pairs, makes the shape of molecule bent since the two lone pairs are pushing the electrons from the two bonded atoms
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Re: H2O VSEPR
2 lone pairs and 2 bonding domains on the central atom in O for H2O forms a "bent" shape
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Re: H2O VSEPR
H2O is bent since there are two bonds formed and two lone pairs which force the bonded oxygens closer to each other.
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