Section 4.3 4.28

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Raymond Le 2G
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Section 4.3 4.28

Postby Raymond Le 2G » Tue Feb 23, 2016 8:20 pm

"Write the full reaction mechanism for the electrophilic addition reaction of hydrogen bromide, HBr, to propene, CH3CHCH2, producing 2-bromopropane, CH3CHBRCH3. Draw the transition states."

Why is it that the H in HBR bonds specifically to the C bonded to two H?

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Joined: Fri Sep 25, 2015 3:00 am

Re: Section 4.3 4.28

Postby 704578485 » Tue Feb 23, 2016 9:05 pm

The H bonds to the the carbon with two hydrogens because this is the way in which every carbon atom will have a full octet. Atoms and molecules tend to want to reach their most stable states and that is when the atoms have full octets. The other carbon atom that does not have a full octet at the start of the reaction achieves it with the C-Br bond.

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