Drawing and labeling reaction profile

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Jacob Afable 3J
Posts: 41
Joined: Fri Sep 25, 2015 3:00 am

Drawing and labeling reaction profile

Postby Jacob Afable 3J » Thu Feb 25, 2016 8:33 pm

4.35 says to draw and label the reaction profile for the reaction: CH3Br + -OH CH3OH + Br-.

For this particular reaction, how do we know that the Gibbs free energy of the reaction between the reactants and products is negative?

For other reactions, how will we know whether G will be positive or negative between the reactants and products?

Alli Foreman 2H
Posts: 26
Joined: Fri Sep 25, 2015 3:00 am

Re: Drawing and labeling reaction profile

Postby Alli Foreman 2H » Thu Feb 25, 2016 10:19 pm

is equal to

If the graph's final point is below the initial point, then that means that and therefore will be negative.

If the graph's final point is above the initial point, then that means that and therefore will be positive.

Jacob Afable 3J
Posts: 41
Joined: Fri Sep 25, 2015 3:00 am

Re: Drawing and labeling reaction profile

Postby Jacob Afable 3J » Sat Feb 27, 2016 3:00 pm

Alli Foreman 2H wrote: is equal to

If the graph's final point is below the initial point, then that means that and therefore will be negative.

If the graph's final point is above the initial point, then that means that and therefore will be positive.



How about for G

Alli Foreman 2H
Posts: 26
Joined: Fri Sep 25, 2015 3:00 am

Re: Drawing and labeling reaction profile

Postby Alli Foreman 2H » Sat Mar 12, 2016 12:03 am

is always positive. It is the difference between the of the reactants and the of the intermediates. intermediates is always above reactants (think of the graph, it's always a hill shape).
So of the intermediates - of the reactants is always positive.


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