## 2009 final 4E

$E_{cell} = E_{cell}^{\circ}-\frac{RT}{nF}\ln Q$

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### 2009 final 4E

Can someone please explain how they jumped from Q to log[H+]?
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Jacqueline Lee
Posts: 21
Joined: Fri Sep 25, 2015 3:00 am

### Re: 2009 final 4E

I think it's because we're looking for pH and the concentrations of Ce3+, Ce4+,MnO4-, and Mn2+ would not contribute to pH because pH is the measure in concentration of H+ so that is what we could focus on instead.

So by taking the E (which would be .157) you can divide that by (.05916/5) and then divide by 8(which came from the exponent of [H] via log rules) and that's how the course reader got the
1.67=log[H+]

Hope that helped

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