## Chapter 1 question 45

$\Delta p \Delta x\geq \frac{h}{4\pi }$

SaniShabgahi3N
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### Chapter 1 question 45

A bowling ball of mass 8.00 kg is rolled down a bowling alley lane at 5.00 +/- 5.0 ms^-1. What is the minimum uncertainty in its position?

Natassia Dunn 3G
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### Re: Chapter 1 question 45

You need to use Heisenberg's uncertainty principle (change in position x change in momentum = h/4pi), change the momentum (delta p) into mass x velocity and then plug in the mass and velocity to solve for the uncertainty in position.

Chem_Mod
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### Re: Chapter 1 question 45

The explanation above is almost correct; you need to plug in the uncertainty in velocity, not the velocity itself. Since the uncertainty is +/- 5 m/s, the entire range of uncertainty is 10 m/s, and this is what you'd plug in for delta V.