## Homework 12.65

Parsia Vazirnia 2L
Posts: 44
Joined: Fri Jul 22, 2016 3:00 am

### Homework 12.65

Why is the answer to part D of 12.65 neutral and not basic with a ph>7?

Posts: 20
Joined: Wed Sep 21, 2016 2:56 pm

### Re: Homework 12.65

It would be very helpful to me and other students if you could copy the question in your post. Unfortunately I don't have my book with me and don't know what question you are referring to. I'm not sure what the answer to part D is, but if it is close to 7, I believe that it could still be considered neutral.

Parsia Vazirnia 2L
Posts: 44
Joined: Fri Jul 22, 2016 3:00 am

### Re: Homework 12.65

Adam Wojnar 4E wrote:It would be very helpful to me and other students if you could copy the question in your post. Unfortunately I don't have my book with me and don't know what question you are referring to. I'm not sure what the answer to part D is, but if it is close to 7, I believe that it could still be considered neutral.

"12.65 Determine whether an aqueous solution of each of the following salts has a pH equal to, greater than, or less than 7. If pH 7 or pH 7, write a chemical equation to justify your answer. (a) NH4Br; (b) Na2CO3; (c) KF; (d) KBr; (e) AlCl3;
(f) Cu(NO3)2."

Pauline Tze 3B
Posts: 57
Joined: Sat Jul 09, 2016 3:00 am
Been upvoted: 1 time

### Re: Homework 12.65

Hi Parsia,

I believe K+ is a weak acid in general and Br- is the conjugate base to a strong acid (HBr) (so the reaction doesn't really go to HBr because strong acid reactions go to completion and not the reverse) so therefore, neither react significantly in water to change the pH.

I hope that helps.

Akshay_Manjarekar_3C
Posts: 9
Joined: Wed Sep 21, 2016 2:58 pm

### Re: Homework 12.65

The reason it is neutral is because the salt is the product of a strong acid and a strong base and so it is a neutral salt. That is why the pH is 7.

NinaSheridan
Posts: 30
Joined: Wed Sep 21, 2016 2:58 pm

### Re: Homework 12.65

If that's the case though, why isn't KF neutral as well?

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