## Self-Test 14.13A

Sue_Park_2D
Posts: 13
Joined: Wed Sep 21, 2016 2:57 pm

### Self-Test 14.13A

I was reading through the textbook and tried to solve out self test 14.13A on page 593.
It says: "Predict the products resulting from the electrolysis of 1 m AgNO3(aq)."
The answer is given to be [Cathode, Ag; anode, O2].

Even after reading the text and previous examples in the section, I don't understand how to determine the answer to this problem.
All I know is that I should look at the half reactions of Ag+ + e- --> Ag and NO3 -+ 2H+ + e- --> NO2 + H2O, but I don't what to do next.

Chem_Mod
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### Re: Self-Test 14.13A

You should be looking at the half reaction of $O_{2} _{(g)} + 4H^{+} _{(aq)} + 4e^{-}\rightarrow 2 H_{2}O_{(l)}$ in addition to the two that you listed for $AgNO_{3} _{(aq)}$. You will see that $Ag$ will have the lowest potential, and that $O_{2}$ will have the highest potential, higher than $NO_{3} _{(aq)}$

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