## Zero Order and k [ENDORSED]

$\frac{d[R]}{dt}=-k; [R]=-kt + [R]_{0}; t_{\frac{1}{2}}=\frac{[R]_{0}}{2k}$

Michelle_Nguyen_3F
Posts: 40
Joined: Wed Sep 21, 2016 2:59 pm

### Zero Order and k

Hello!

So I know that if we plot [A] vs time and we get a straight line, then the zero order reaction has a slope of -k. However, is it possible for k to be positive as well? Thank you!

Timothy_Yu_Dis3A
Posts: 11
Joined: Wed Sep 21, 2016 2:58 pm
Been upvoted: 1 time

### Re: Zero Order and k  [ENDORSED]

For [A] vs. Time and a zero order reaction, I think k is always equal to negative slope. We only get a positive k when we have a second order reaction for the plot of 1/[A] vs. Time.

Ariana de Souza 4C
Posts: 99
Joined: Wed Sep 21, 2016 2:56 pm

### Re: Zero Order and k

but the slope is -k. So wouldn't k have to be positive, for there to be a negative slope?