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For the pre-equilibrium approach example why is there a 2 in front of the reaction constant? Is it because 2 products (2NO2 ) are formed? Also, is the intermediate only present in the rate law if the first reaction is fast and the second reaction is slow?
Yes you are correct! The 2 in front of the reaction constant is there because there are 2 NO2 formed. And yes, the intermediate is the product of the reaction for a fast step and is the reactant of the slow step.
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