## 2016 Final

$\Delta G^{\circ}= \Delta H^{\circ} - T \Delta S^{\circ}$

$\Delta G^{\circ}= -RT\ln K$

$\Delta G^{\circ}= \sum \Delta G_{f}^{\circ}(products) - \sum \Delta G_{f}^{\circ}(reactants)$

Blake_Katsev_2E
Posts: 113
Joined: Wed Sep 21, 2016 2:57 pm

### 2016 Final

Why in question 2A when the question says that each of the two reactants have half of the partial pressure as the single product would the K=2x/x^2 rather than K=x/(x/2)^2

Sangita_Sub_3H
Posts: 23
Joined: Sat Jul 09, 2016 3:00 am

### Re: 2016 Final

I think it's because it is easier to use whole numbers instead of fractions, since half of 2x would be x. However, I think both ways should yield the same result.

Blake_Katsev_2E
Posts: 113
Joined: Wed Sep 21, 2016 2:57 pm

### Re: 2016 Final

i calculated it and i got different results

Aliya Habib 1L
Posts: 20
Joined: Fri Sep 25, 2015 3:00 am

### Re: 2016 Final

The overall pressure of the reactants is half the pressure of the product not that cl3 and cl2 are halves. So the denominator is still x^2 but the overall relationship between the reactants and products is that the reactants are half which I believe is why you would multiply by 2 instead of multiplying by 1/2 for convenience.

Or it could be a typo

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