Midterm 2013 6a

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Andrew M 2J
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Joined: Wed Sep 21, 2016 2:58 pm

Midterm 2013 6a

Postby Andrew M 2J » Sat Mar 18, 2017 8:17 pm

For this cycloalkene, how come this figure cannot be named 2,3,4,4-tetramethylcyclo-1-hexene?

Nikhil_Madan_3C
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Re: Midterm 2013 6a

Postby Nikhil_Madan_3C » Sat Mar 18, 2017 8:33 pm

This is because the numbering must follow the direction of the double bond. Naming it as 2,3,4,4-tetramethylcyclo-1-hexene would make the number second double bonded carbon as 6, which would be incorrect since double bond carbon atoms are assigned the smallest possible locator numbers unless there is a functional group present.

Andrew M 2J
Posts: 9
Joined: Wed Sep 21, 2016 2:58 pm

Re: Midterm 2013 6a

Postby Andrew M 2J » Sat Mar 18, 2017 8:44 pm

Sorry this is supposed to be for FINAL 2013

Noelle Min-1N
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Joined: Wed Sep 21, 2016 2:58 pm

Re: Midterm 2013 6a

Postby Noelle Min-1N » Sat Mar 18, 2017 8:46 pm

The double bond would be on the 1st and 2nd carbon, not the 6. I also thought it would be 2, 3, 4, 4- tetramethylcyclo-1-hexene...


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