Hey guys!
Here are my answers for Self Test 1 -- What do you get?
1a. 24.0 g NaOH
1b. 81.3 mL
2a. 2AL + 6HCL --> 2AlCl3 + 3H2
2b. 9.51g AlCl3
3a. Dx >= 3.2 E -32
3b. 1.3 E -31 m
4. 3.61 E -19 J
5. CH4O
6. 2.98 J
7. 2CH3OH + 3O2 --> 2CO2 + 4H20
8. 1.86 E -6 m
9. C5H12O5
10. (drew a sine wave graph)
Amplitude = height of the waves = the intensity of the wave and/or the number of photons
Frequency = peak to peak distance = how many cycles pass in 1 second
Wavelength = distance between origin and 1 full cycle = the length of the wave's oscillations .
Self Test 1 Answers
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Re: Self Test 1 Answers
Could you explain how you set up 1B? I think I'm overthinking the entire thing. Thanks!
Re: Self Test 1 Answers
Davalanya 1F wrote:Could you explain how you set up 1B? I think I'm overthinking the entire thing. Thanks!
You just multiply 250mL by .650 M and divide that by 2.00M. The M's will cancel out and leave you with about 81.3mL
Last edited by Nahal 1F on Wed Jul 05, 2017 2:53 pm, edited 1 time in total.
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Re: Self Test 1 Answers
Ben's answer for number 5 is correct. Dr. Lavelle used C3HO4 as an example in the post when he divided the respective number of moles by the lowest value of moles.
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Re: Self Test 1 Answers
Hey guys, how did you get no.5, I got an extremely small number, I think I might have got some steps wrong.
Re: Self Test 1 Answers
Chels Zh wrote:Hey guys, how did you get no.5, I got an extremely small number, I think I might have got some steps wrong.
This is what I did. Not sure if it's right though
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Re: Self Test 1 Answers
Yes, your work is correct up to your mol ratio at the end. I do not know where .2 C and .2 O come from. Your ratio should be C: 1 H: 4 O:1 giving you the final answer of CH4O.
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Re: Self Test 1 Answers
Why is it that the produced grams for CO2 only apply to carbon? and respectively the same for H2O and Hydrogen?
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