Self Test 1 Answers

[Ben Rolnik 1D]

Hey guys!

Here are my answers for Self Test 1 -- What do you get?

1a. 24.0 g NaOH
1b. 81.3 mL

2a. 2AL + 6HCL --> 2AlCl3 + 3H2
2b. 9.51g AlCl3

3a. Dx >= 3.2 E -32
3b. 1.3 E -31 m

4. 3.61 E -19 J

5. CH4O

6. 2.98 J

7. 2CH3OH + 3O2 --> 2CO2 + 4H20

8. 1.86 E -6 m

9. C5H12O5

10. (drew a sine wave graph)
Amplitude = height of the waves = the intensity of the wave and/or the number of photons
Frequency = peak to peak distance = how many cycles pass in 1 second
Wavelength = distance between origin and 1 full cycle = the length of the wave's oscillations .

[Davalanya 1F]

Could you explain how you set up 1B? I think I'm overthinking the entire thing. Thanks!

[Nahal 1F]

Could you explain how you set up 1B? I think I'm overthinking the entire thing. Thanks!

You just multiply 250mL by .650 M and divide that by 2.00M. The M's will cancel out and leave you with about 81.3mL

[Davalanya 1F]

5. is C3HO4

I checked with an old post from Lavelle.
viewtopic.php?t=2309

[Paul Wong1B]

Ben's answer for number 5 is correct. Dr. Lavelle used C3HO4 as an example in the post when he divided the respective number of moles by the lowest value of moles.

[Chels Zh 1D]

Hey guys, how did you get no.5, I got an extremely small number, I think I might have got some steps wrong.

[Nahal 1F]

Hey guys, how did you get no.5, I got an extremely small number, I think I might have got some steps wrong.

This is what I did. Not sure if it's right though

[Sarahi Cota-Felix 1C]

Yes, your work is correct up to your mol ratio at the end. I do not know where .2 C and .2 O come from. Your ratio should be C: 1 H: 4 O:1 giving you the final answer of CH4O.

[lnlyzelda_3J]

Why is it that the produced grams for CO2 only apply to carbon? and respectively the same for H2O and Hydrogen?