Clarification on C=λv
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Re: Clarification on C=λv
When you multiply wavelength by frequency, you should end up with c (speed of light). If both increase the desired value (3.00 x 10^8 m/s) will be overshot/missed. Therefore, as you increase one, the other must me decreased because the speed of light is a constant.
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Re: Clarification on C=λv
Yes, c is a constant. C is the speed of light and does not change. Therefore, in all C=λv problems, you should set c equal to 3.00*10^8 m/s. The wavelength and frequency are what will change in this equation.
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Re: Clarification on C=λv
Wavelength and frequency are inversely proportional to each other which means if frequency increases then wavelength decreases or vice versa.
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Re: Clarification on C=λv
Since speed of light is constant (3.00 x 10^8 m/s) and therefore cannot change, if wavelength increases, frequency must decrease to keep their product equal to speed of light.
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Re: Clarification on C=λv
When frequency decreases, wavelength will increase because the speed of light is constant.
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Re: Clarification on C=λv
Is it safe to say that electromagnetic radiation and wavelength are inversely proportional, while frequency and electromagnetic radiation are directly related, based on the responses above?
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Re: Clarification on C=λv
Energy of a photon=hv
c=λν or v=c/λ
Therefore, E=h(c/λ)
So, you could say energy of a photon and wavelength are inversely proportional while energy and frequency are directly proportional.
c=λν or v=c/λ
Therefore, E=h(c/λ)
So, you could say energy of a photon and wavelength are inversely proportional while energy and frequency are directly proportional.
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