CH.1 #33 pt B

Moderators: Chem_Mod, Chem_Admin

mendozayael_2H
Posts: 31
Joined: Fri Sep 29, 2017 7:06 am

CH.1 #33 pt B

Postby mendozayael_2H » Mon Oct 09, 2017 12:11 am

#1.33 says: "The velocity of an electron that is emitted from a metallic surface by a photon is 3.6 X 10^3 km/s. (a) What is the wavelength of the ejected electron? (b) No electrons are emitted from the surface of the metal until the frequency of the radiation reaches 2.50 X 10^16 Hz. How much energy is required to remove the electron from the metal surface?"

Chem_Mod
Posts: 23858
Joined: Thu Aug 04, 2011 1:53 pm
Has upvoted: 1253 times

Re: CH.1 #33 pt B

Postby Chem_Mod » Mon Oct 09, 2017 2:26 pm

Hello,

What part of the question do you not understand?

Elizabeth Bamishaye 2I
Posts: 54
Joined: Fri Sep 29, 2017 7:04 am

Re: CH.1 #33 pt B

Postby Elizabeth Bamishaye 2I » Tue Oct 10, 2017 5:34 pm

For part A, you determine the mass of electrons, which is . Then you change the given velocity from kilometers to meters and after that use the equation or basically to get the answer for part A.

For part b, you use to get the answer for part B.

Clara Hu 1G
Posts: 50
Joined: Sat Jul 22, 2017 3:00 am
Been upvoted: 1 time

Re: CH.1 #33 pt B

Postby Clara Hu 1G » Wed Oct 11, 2017 4:53 pm

For part b, use . Because you know the velocity of the ejected electron and the frequency of the radiation, you can solve for the work function, which is the energy required to remove the electron, and get 1.66 x 10-17 J.


Return to “Photoelectric Effect”

Who is online

Users browsing this forum: No registered users and 5 guests