Naming (steps)

[ZoeHahn1J]

Is there a systematic way to name all coordination compounds? What are the steps? Thanks so much!

[Anna Goldberg 2I]

1) Identify the Greek prefix that corresponds with the coordination number (how many ligands are bonded)
2) When naming, name the ligands in alphabetical order
3) Then after you have named all of the ligands in alphabetical order, then name the Transition Metal Cation and then it's Roman Numeral in parenthesis
4) If the transition metal is an anion, add "ate" at the end of the transition metal name
From Dr. Lavelle's lecture, here is [Co(NH3)5Cl]Cl2H20
I first start out by seeing that there are five ammonia (NH3). This corresponds to the prefix of "penta." When naming, ammonia is "ammine"
The other ligand, Chlorine, is "chloro" when naming.
Since ammine is in front of chloro in the alphabet, I will name pentammine first.
The transition metal cation is cobalt, and the charge on cobalt is positive two, thus the Roman Numeral II.
Cl2 is chloride, and H2O is dihydrate.
Thus, following the steps above, the name is Pentaamminechlorocobalt(II) Chloride Dihydrate

[YashDeshmukh1D]

Since some transition metals can vary in charge, how do you determine what Roman numeral to place after the transition metal?

[Emily Mei 1B]

The roman numeral is the oxidation state of the transition metal. You determine that based on the overall charge of the compound, and on the individual charges of everything else in the compound.

[RenuChepuru1L]

at what point should you figure out cations versus anions and is there an easy way to do that?

[AtreyiMitra2L]

at what point should you figure out cations versus anions and is there an easy way to do that?

The cations are what has an overall positive charge and the anions are what has an overall negative charge.

[Alissa Stanley 3G]

To determine what Roman numeral to put after a transition metal, you must first identify the charge of every other element in the compound. You then add up the charges of all of the other elements, and the transition metal charge will be whatever will make that compound have charge of 0. So if the other elements add up to -2, the transition metal will have a (II) after it.