CH 17 #31

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CH 17 #31

Postby donnanguyen1d » Sun Nov 26, 2017 5:55 pm

for part D the answer is Na {Fe (OH2)2(C2O4)2} Why is OH2 before C2O4? I thought they had to be in alphabetical order

Dylan Davisson 2B
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Re: CH 17 #31

Postby Dylan Davisson 2B » Sun Nov 26, 2017 6:59 pm

I think the reason that OH2 comes before C2O4 is because of the charge of the ligand. OH2 is neutral, so it comes before the negatively charged C2O4. When the ligands have the same charge, they should be put into alphabetical order.

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