Reverse Reactions [ENDORSED]

[welcometochillis]

If the k value for a system in equilibrium is a number, will it's reverse reaction be the same number? I assume yes because the rate at which products and reactants "go" into another should be the same?

[Carlos Gonzales 1H]

The K value of the reverse reaction will be the reciprocal of the forward reaction, so the reverse reaction will be 1/K.

[Kathleen Vidanes 1E]

No,the K value for the reverse reaction would be the inverse of the forward reaction. Using the example given in class, if the K value for the forward reaction = 61.0, the K value for the reverse reaction will = 1/61.0 or 0.016

[CameronJohari1J]

The k value of the reverse reaction is inverse of k.
If k is the equilibrium value for A+B<-->C K=C/(A*B)
then C<-->A+B 1/K=(A*B)/C