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Isaac Eyler 1E
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Joined: Fri Sep 29, 2017 7:04 am


Postby Isaac Eyler 1E » Tue Dec 05, 2017 5:15 pm

In 12.3d, the acid HCOOH donates its proton to become the conjugate base HCO2^-

I understand this problem, but I was wondering, is it wrong to write HCOO^- as opposed to what the solutions manual says (HCO2^-)?

Is there a difference?

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Re: HCOOH to HCO2^-

Postby kaushalrao2H » Tue Dec 05, 2017 5:17 pm

i think either way is fine, but if you write the formula as HCOO-, you emphasize the point that the carboxyl group in HCOOH has lost a H+ ion.

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