Question about Problem 8.41

[Isa Samad 1L]

In the solutions manual, the answer uses the equation -q(water) = q(ice). Is this because the ice is lowering the temperature of the water?

[Ashin_Jose_1H]

Yeah. The heat from the water is transferred to the ice.

[Erica Nagase 1H]

The liquid water will lose heat and its temperature will decrease, and the ice will absorb that heat and melt/temperature will increase. This is why the q(water) is negative and q(ice) is positive.

[Johann Park 2B]

Yes, in thermodynamics we must remember that energy is conserved and that q_sys + q_surr = 0, and thus q_sys = -q_surr; the system being the ice and the surroundings being the water.

[Meredith Steinberg 2E]

Yes because there is a transfer of heat from the water to the ice

[Ashley Macabasco 2K]

In the solution manual -q(water)=q(ice) illustrates that heat from water is being transferred exothermically to the ice shown with the lose of heat (-q). The ice is then gaining heat endothermically from the water which can also be seen with q being positive for ice.