In both of these homework problems, the solution manual provides necessary equations out of thin air:
for 8.65, N2(g) + (5/2)O2(g) --> N2O5(g)
for 8.67, H2(g) + (1/2)O2(g) --> H2O(l)
Where do these equations come from? For question 8.65, I found the correct answer without using that equation. I wasn't even sure how to start 8.67 without the solution manual. Help
8.65 and 8.67
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Re: 8.65 and 8.67
These are just the overall equations that get you to the necessary product. That is, you must alter the equations provided in 65 to get to that overall equation. To do that, you can multiply the second equation by 1/2. This will allow 2 NO2 to cancel, and we want this to cancel because it is not included in the equation to reach the product.
Hope this helps!
Hope this helps!
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Re: 8.65 and 8.67
Conversely you could also multiply the first equation by 2 to get 4 NO + 2 O2 --> 4 NO2. In this case you would also have to multiply the deltaH by 2. Then the 4 NO2s would cancel out leaving you with the first equation being 4 NO + 2 O2 --> and the second equation with O2 --> 2 N2O5. You would then add the two equations together to get 4 NO + 3 O2 --> 2 N2O5 with a deltaH of -338.4 kJ. You would then find deltaH for one mol of N2O5 rather than 2.
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