Question about Problem 8.41
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Question about Problem 8.41
In the solutions manual, the answer uses the equation -q(water) = q(ice). Is this because the ice is lowering the temperature of the water?
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Re: Question about Problem 8.41
The liquid water will lose heat and its temperature will decrease, and the ice will absorb that heat and melt/temperature will increase. This is why the q(water) is negative and q(ice) is positive.
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Re: Question about Problem 8.41
Yes, in thermodynamics we must remember that energy is conserved and that qsys + qsurr = 0, and thus qsys = -qsurr; the system being the ice and the surroundings being the water.
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Re: Question about Problem 8.41
In the solution manual -q(water)=q(ice) illustrates that heat from water is being transferred exothermically to the ice shown with the lose of heat (-q). The ice is then gaining heat endothermically from the water which can also be seen with q being positive for ice.
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