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Nishma Chakraborty 1J
Posts: 51
Joined: Fri Sep 29, 2017 7:04 am


Postby Nishma Chakraborty 1J » Sat Jan 20, 2018 2:35 pm

This problem reads: Use the bond enthalpies in Tables 8.6 and 8.7 to estimate
the reaction enthalpy for (a) 3 C2H2(g) --> C6H6(g).

When we're calculating bonds broken vs. the bonds formed, why does the solutions manual not account for the C-H bonds?

Thank you!

Emily Glaser 1F
Posts: 156
Joined: Thu Jul 27, 2017 3:01 am

Re: 8.73a

Postby Emily Glaser 1F » Sat Jan 20, 2018 2:41 pm

Think of a resonance structure, the C-H are bounded and when you have 3 moles of c2h2, you are not breaking those c-h bonds or forming. You are putting the c-c bonds together. Look up c6h6 on internet.

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