Moderators: Chem_Mod, Chem_Admin

Emily Glaser 1F
Posts: 156
Joined: Thu Jul 27, 2017 3:01 am


Postby Emily Glaser 1F » Sat Jan 20, 2018 5:26 pm

I don't understand how the net moles produced was 2/3.

Also, where did the 1/3 applied to the delta H come from at the end of the solution?

Yiwei Zhou 2I
Posts: 21
Joined: Fri Sep 29, 2017 7:07 am

Re: 8.117

Postby Yiwei Zhou 2I » Sun Jan 21, 2018 11:20 pm

For the production of 1.00 mol H2, you have 1/3 mol CH4, 1/3 mol H20, and 1/3 mol CO2 produced. So the net mole of gas is 2/3 mol.

Adrian Lim 1G
Posts: 88
Joined: Fri Sep 29, 2017 7:03 am

Re: 8.117

Postby Adrian Lim 1G » Wed Jan 24, 2018 10:26 pm

The delta H given is for 1 mole of reaction or 3 moles of H2. However, the question is asking for the change for the production of only one mole. Thus, you would have to take the given delta H and divide it by 3

Return to “Reaction Enthalpies (e.g., Using Hess’s Law, Bond Enthalpies, Standard Enthalpies of Formation)”

Who is online

Users browsing this forum: No registered users and 1 guest