## 9.65

$\Delta G^{\circ}= \Delta H^{\circ} - T \Delta S^{\circ}$

$\Delta G^{\circ}= -RT\ln K$

$\Delta G^{\circ}= \sum \Delta G_{f}^{\circ}(products) - \sum \Delta G_{f}^{\circ}(reactants)$

Ammarah 2H
Posts: 30
Joined: Fri Sep 29, 2017 7:06 am

### 9.65

I understand how to do the problem, but I was just wondering: why do we only have to calculate delta S and not both delta S and delta H? Thank you!

Kayla Danesh 1F
Posts: 38
Joined: Thu Jul 13, 2017 3:00 am

### Re: 9.65

I think its because the question is asking specifically about a temperature change with only has to do with the TdeltaS term, not the deltaH term. It's asking with respect to only temperature, not the entire Gibbs free energy equation.

Ammarah 2H
Posts: 30
Joined: Fri Sep 29, 2017 7:06 am

### Re: 9.65

So do we just assume that delta H is positive?

Vasiliki G Dis1C
Posts: 53
Joined: Fri Sep 29, 2017 7:04 am

### Re: 9.65

I could be wrong on this, but I think since they are only referring to a temperature change, they just want you to look at ΔS. In that case, we can assume ΔH is constant or has no effect on the ΔG. Hope this helps!