## Maximum Energy Able to Do Work [ENDORSED]

$\Delta G^{\circ}= \Delta H^{\circ} - T \Delta S^{\circ}$

$\Delta G^{\circ}= -RT\ln K$

$\Delta G^{\circ}= \sum \Delta G_{f}^{\circ}(products) - \sum \Delta G_{f}^{\circ}(reactants)$

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### Maximum Energy Able to Do Work

I remember in lecture that Dr. Lavelle mentioned that Gibb's Free Energy should really be called Gibb's available energy since when ∆G < 0, Gibb's free energy can be thought of as the maximum energy that a system can use to do work. I'm guessing that since Dr. Lavelle specified this definition under conditions when ∆G < 0 that when ∆G > 0, this does not hold true. In other words, does the definition of Gibb's free energy as the maximum energy that a system can use to do work hold true when the reaction in question is non-spontaneous?

Chem_Mod
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### Re: Maximum Energy Able to Do Work  [ENDORSED]

∆Gsys > 0 then it is the maximum work being done on the system.

Good luck everyone with your midterm.

OliviaShearin2E
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### Re: Maximum Energy Able to Do Work

Can someone clarify what types of work? Some sites say maximum reversible work and others say maximum nonexpansion work.

Sirajbir Sodhi 2K
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### Re: Maximum Energy Able to Do Work

Maximum useful (nonexpansion) work is associated with Gibb's Free Energy.