Delta G=-nFE

[John Huang 1G]

A lot of the problems do not have moles given, so when we are using DeltaG=-nFE, what value would we use for n?

[Dylan Mai 1D]

do you have an example of one of the problems that does this?

[Rachel Formaker 1E]

Moles in the equation ΔG=-nFE is for moles of electrons, so even if the moles of a substance are not explicitly given, you should be able to figure out the moles of electrons through the redox half-reactions.

[Julie Steklof 1A]

After writing balanced half reactions, you will be able to see the moles of electrons involved in the redox reaction. This is the number you use for n.

[Ivy Lu 1C]

The n in the equation is the moles of electrons transferred. To find the electrons transferred, you'll have to write the two half-reactions and balance them.

[Jeremiah Samaniego 2C]

The n in the equation is the moles of electrons transferred. To find the electrons transferred, you'll have to write the two half-reactions and balance them.

A good example of this is homework problem 14.9.a):

Given the overall equation 2 Ce⁴⁺ (aq) + 3 I^- (aq) --> 2 Ce³⁺ (aq) + I₃^- (aq), the half reactions would be:
2 Ce⁴⁺ (aq) + 2 e^- --> 2 Ce³⁺ (aq) and 3 I^- (aq) --> I₃^- (aq) + 2 e^-.

Since 2 moles of electrons are being transferred in the overall reaction, you would plug in 2 for n in the equation Delta G = -nFE