14.31

[Wenting Hu 2H]

for 14.31 how do we determine if the reaction has k>1? Is it cathode/anode?

[Samantha Kan 2L]

You use E(cathode)-E(anode) to find the standard E. If E is positive, it favors the products so k>1.

[Luke Bricca 1H]

Furthermore, you could also solve the Nernst equation for K which would show its sign. This would be more work and is inefficient but guarantees a correct answer.

[Phillip Winters 2F]

Also if K>1, meaning that E>1 as well, then the reaction would be spontaneous in the forward direction

[Ashley Macabasco 2K]

If E(cathode)>E(anode) then K>1 and products are favored.

[Matthew Lee 3L]

If the E is positive, this means that deltaG is negative which means the reaction is favorable. When it is favorable, there will be a higher concentration of products, causing K to be greater than 1.

[204932558]

If Ecell is positive, G is negative according to G=-nEf. It means the forward reaction is spontaneous and therefore favored, resulting in a K greater than 1.