5.13

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Helen Shi 1J
Posts: 78
Joined: Sat Jul 22, 2017 3:00 am

5.13

Postby Helen Shi 1J » Mon Feb 26, 2018 11:00 pm

Can someone explain 5.13 and how to get the initial reaction rate?

Sabrina Dunbar 1I
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Re: 5.13

Postby Sabrina Dunbar 1I » Mon Feb 26, 2018 11:10 pm

I am assuming you mean 15.13 or else I would be doing the wrong problem! First, you have to convert the grams of reactants given into moles, and then from moles to their respective molarity values. You get these values to be 0.347 mol/L and 0.001 mol/L. Then, multiple these values and the given k together, nd that should help you reach the correct answer.

Johann Park 2B
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Re: 5.13

Postby Johann Park 2B » Tue Feb 27, 2018 11:01 am

Convert grams to mols using molar masses of H2 and I2. Then use .750 L to convert it to Molarity. You should have roughly 0.35 mol/L H2 and 0.001 mol/L I2.

Rate = k[H2][I2]

Rate = 2.2 x 10-5 mol/(L x S)


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