15.23
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15.23
For Part C, why did you have to subtract (2(.034molB)) from (.153 molA) to get [A]t, I thought calculating [A]t would only require multiplying .034molB by 2?
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Re: 15.23
I believe it's because the equation of the reaction given is 2A B + C so we need to account for the ratio of 2 mol A used to 1 mol B produced.
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Re: 15.23
You start with the initial concentration of A, and you need to find how much b is produced to see how much the concentration of A decreases. Therefore, you would subtract 2*b from the initial concentration of A
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Re: 15.23
For product to form, there must be something taken from the reactant. Therefore, you take the initial concentration of A and subtract the concentration that has been used to create B at time t.
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