## graphs

$aR \to bP, Rate = -\frac{1}{a} \frac{d[R]}{dt} = \frac{1}{b}\frac{d[P]}{dt}$

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Joined: Fri Sep 29, 2017 7:03 am

### graphs

What would the graphs for the three orders look like?

Hazem Nasef 1I
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Joined: Tue Oct 10, 2017 7:13 am

### Re: graphs

For a zero order reaction, a graph of [A] vs time will produce a straight line with a negative slope. For a first order reaction, a graph of ln([A]) vs time will produce a straight line with a negative slope. For a second order reaction, a graph of 1/[A] vs time will produce a straight line with a positive slope.

Jimmy Zhang Dis 1K
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