Friday Lecture


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Samira 2B
Posts: 38
Joined: Fri Sep 29, 2017 7:05 am

Friday Lecture

Postby Samira 2B » Sun Mar 04, 2018 9:37 pm

I understand the concept of intermediate species. I just do not get how just from the NO2 eqn and the rate eqn, we got that an intermediate species is needed. In the lecture notes, Lavelle states that "NO2 cannot form NO and CO2 so there must be an intermediate species" but in the eqn itself, there is a CO that helps form it? (Is it because the CO is a zero order?)

Caroline Cox 1H
Posts: 18
Joined: Fri Sep 29, 2017 7:03 am

Re: Friday Lecture

Postby Caroline Cox 1H » Sun Mar 04, 2018 9:52 pm

Yes, it is because CO2 is zero order and therefore is not a factor that determines rate (aka not in the slow step).

Wenjie Dong 2E
Posts: 53
Joined: Fri Jun 23, 2017 11:40 am

Re: Friday Lecture

Postby Wenjie Dong 2E » Sun Mar 04, 2018 11:09 pm

It's because CO2 is the other reactant in this reaction. Since it does not occur in the reaction of NO2, there must be a subsequent reaction that involves CO2.

Caroline LaPlaca
Posts: 30
Joined: Sat Jul 22, 2017 3:01 am

Re: Friday Lecture

Postby Caroline LaPlaca » Sun Mar 04, 2018 11:39 pm

It’s because of CO2

Miguel Velasco 2J
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Joined: Fri Sep 29, 2017 7:07 am
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Re: Friday Lecture

Postby Miguel Velasco 2J » Sun Mar 04, 2018 11:42 pm

CO2 is zero order and is needed

aaron tang 2K
Posts: 49
Joined: Thu Jul 27, 2017 3:01 am

Re: Friday Lecture

Postby aaron tang 2K » Mon Mar 05, 2018 2:15 pm

Correct, CO2 is a zero order so it doesn't affect the determination rate or the slow step.


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