## Friday Lecture

$K = \frac{k_{forward}}{k_{reverse}}$

Samira 2B
Posts: 38
Joined: Fri Sep 29, 2017 7:05 am

### Friday Lecture

I understand the concept of intermediate species. I just do not get how just from the NO2 eqn and the rate eqn, we got that an intermediate species is needed. In the lecture notes, Lavelle states that "NO2 cannot form NO and CO2 so there must be an intermediate species" but in the eqn itself, there is a CO that helps form it? (Is it because the CO is a zero order?)

Caroline Cox 1H
Posts: 18
Joined: Fri Sep 29, 2017 7:03 am

### Re: Friday Lecture

Yes, it is because CO2 is zero order and therefore is not a factor that determines rate (aka not in the slow step).

Wenjie Dong 2E
Posts: 53
Joined: Fri Jun 23, 2017 11:40 am

### Re: Friday Lecture

It's because CO2 is the other reactant in this reaction. Since it does not occur in the reaction of NO2, there must be a subsequent reaction that involves CO2.

Caroline LaPlaca
Posts: 30
Joined: Sat Jul 22, 2017 3:01 am

### Re: Friday Lecture

It’s because of CO2

Miguel Velasco 2J
Posts: 40
Joined: Fri Sep 29, 2017 7:07 am
Been upvoted: 1 time

### Re: Friday Lecture

CO2 is zero order and is needed

aaron tang 2K
Posts: 49
Joined: Thu Jul 27, 2017 3:01 am

### Re: Friday Lecture

Correct, CO2 is a zero order so it doesn't affect the determination rate or the slow step.