Self Test 15.3Ba

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Kathleen Vidanes 1E
Posts: 62
Joined: Fri Sep 29, 2017 7:07 am

Self Test 15.3Ba

Postby Kathleen Vidanes 1E » Tue Mar 06, 2018 5:01 pm

On page 620, Self-Test 15.3B reads:

When the concentration of 2-bromo-2-methylpropane, C4H9Br, is doubled, the rate of the reaction C4H9Br(aq)+OH-(aq) --> C4H9OH(aq)+ Br- (aq) increases by a factor of 2. When both the C4H9Br and the OH- concentrations are doubled, the rate increase is the same, a factor of 2. What are (a) the reactant orders?

I know that the reactant order for C4H9Br is 1, because as C4H9Br is doubled, so is the rate. However, I am unsure about the order for OH-. Would it be zero-order? Why or why not?

Rachel Brown 3A
Posts: 52
Joined: Fri Sep 29, 2017 7:06 am

Re: Self Test 15.3Ba

Postby Rachel Brown 3A » Tue Mar 06, 2018 5:10 pm

Based on reading the question, my initial reaction would be that it is zero-order for the OH- because I see no other possibility for the concentration change of OH- to not affect the rate. Considering that the definition of a zero-order reaction is that the rate is not dependent on concentrations, I would say this is a fair conclusion.


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