graph of 0 order

[Ekayana Sethi 2K]

What would the differential rate law graph of 0 order reactions look like? how would we graph [A]o against the initial rates? would it be a positive slope negative slope or a line parallel to x or y axis?

[Grace Han 2K]

For rxn rate vs time, the graph will have a horizontal line and then abruptly fall to zero when all the reactants are consumed.
For the integrated zero rate law, it will look similar to the graph of first-order integrated rate law where the slope= -k

[Grace Han 2K]

Go to Dr. Lavelle's page, and under Math Assistance, there is a Kinetic file. There is a detailed graph on page 3.

[CalebBurns3L]

rate is constant, which means that the graph would be a horizontal line until all the reactants are used up and the rate instantly drops to zero.

[Emma Miltenberger 2I]

The graph of a 0 order reaction plots time and concentration. The graph is linear and has a slope of -k and a y intercept of the initial concentration.

[Veronica Rasmusen 2B]

For differential rate law, you would graph rate vs. concentration, and since rate only depends on k and not concentration, it would be a horizontal line that drops straight down when the reactants are consumed.
For integrated rate law, you graph concentration vs. time for zero order reactions, the y-intercept would be [A]_o, and it would appear as a linear plot with slope = -k

[Yeyang Zu 2J]

The graph is a linear line with time against [A]. The slope is negative, which equals to -k. The interaction point with y-axis is [A]0, which is the initial concentration of the reactant.

[Jimmy Zhang Dis 1K]

[Yeyang Zu 2J]

It would be a negative slope linear line. Y axis is reaction concentration, whose interaction is A0. The x axis is time, as time goes, the reactants consumes and its concentration decreases

[Jennie Fox 1D]

The graph would be a horizontal line that abruptly drops straight down to zero (once all of the reactants are used up)

[Cynthia Bui 2H]

The line would be parallel to the x-axis.