graph of 0 order


Moderators: Chem_Mod, Chem_Admin

Ekayana Sethi 2K
Posts: 47
Joined: Wed Nov 16, 2016 3:03 am
Been upvoted: 1 time

graph of 0 order

Postby Ekayana Sethi 2K » Thu Mar 08, 2018 4:19 pm

What would the differential rate law graph of 0 order reactions look like? how would we graph [A]o against the initial rates? would it be a positive slope negative slope or a line parallel to x or y axis?

Grace Han 2K
Posts: 33
Joined: Tue Nov 15, 2016 3:00 am

Re: graph of 0 order

Postby Grace Han 2K » Thu Mar 08, 2018 4:40 pm

For rxn rate vs time, the graph will have a horizontal line and then abruptly fall to zero when all the reactants are consumed.
For the integrated zero rate law, it will look similar to the graph of first-order integrated rate law where the slope= -k

Grace Han 2K
Posts: 33
Joined: Tue Nov 15, 2016 3:00 am

Re: graph of 0 order

Postby Grace Han 2K » Thu Mar 08, 2018 4:52 pm

Go to Dr. Lavelle's page, and under Math Assistance, there is a Kinetic file. There is a detailed graph on page 3.

CalebBurns3L
Posts: 47
Joined: Fri Sep 29, 2017 7:07 am

Re: graph of 0 order

Postby CalebBurns3L » Fri Mar 09, 2018 12:23 pm

rate is constant, which means that the graph would be a horizontal line until all the reactants are used up and the rate instantly drops to zero.

Emma Miltenberger 2I
Posts: 51
Joined: Thu Jul 27, 2017 3:00 am

Re: graph of 0 order

Postby Emma Miltenberger 2I » Fri Mar 09, 2018 1:37 pm

The graph of a 0 order reaction plots time and concentration. The graph is linear and has a slope of -k and a y intercept of the initial concentration.

Veronica Rasmusen 2B
Posts: 49
Joined: Sat Jul 22, 2017 3:01 am

Re: graph of 0 order

Postby Veronica Rasmusen 2B » Sat Mar 10, 2018 6:09 pm

For differential rate law, you would graph rate vs. concentration, and since rate only depends on k and not concentration, it would be a horizontal line that drops straight down when the reactants are consumed.
For integrated rate law, you graph concentration vs. time for zero order reactions, the y-intercept would be [A]o, and it would appear as a linear plot with slope = -k

Yeyang Zu 2J
Posts: 58
Joined: Fri Sep 29, 2017 7:06 am

Re: graph of 0 order

Postby Yeyang Zu 2J » Sun Mar 11, 2018 1:37 pm

The graph is a linear line with time against [A]. The slope is negative, which equals to -k. The interaction point with y-axis is [A]0, which is the initial concentration of the reactant.

Jimmy Zhang Dis 1K
Posts: 30
Joined: Fri Sep 29, 2017 7:05 am

Re: graph of 0 order

Postby Jimmy Zhang Dis 1K » Sun Mar 11, 2018 11:50 pm

Image

Yeyang Zu 2J
Posts: 58
Joined: Fri Sep 29, 2017 7:06 am

Re: graph of 0 order

Postby Yeyang Zu 2J » Sat Mar 17, 2018 12:03 am

It would be a negative slope linear line. Y axis is reaction concentration, whose interaction is A0. The x axis is time, as time goes, the reactants consumes and its concentration decreases

Jennie Fox 1D
Posts: 66
Joined: Sat Jul 22, 2017 3:01 am

Re: graph of 0 order

Postby Jennie Fox 1D » Sat Mar 17, 2018 12:42 am

The graph would be a horizontal line that abruptly drops straight down to zero (once all of the reactants are used up)

Cynthia Bui 2H
Posts: 30
Joined: Fri Sep 29, 2017 7:05 am

Re: graph of 0 order

Postby Cynthia Bui 2H » Sat Mar 17, 2018 11:46 am

The line would be parallel to the x-axis.


Return to “Zero Order Reactions”

Who is online

Users browsing this forum: No registered users and 2 guests