zero order rate?

$\frac{d[R]}{dt}=-k; [R]=-kt + [R]_{0}; t_{\frac{1}{2}}=\frac{[R]_{0}}{2k}$

Jasmine Botello 2F
Posts: 67
Joined: Fri Sep 29, 2017 7:04 am

zero order rate?

In my notes, I wrote down that for a zero order the rate does not depend on concentration.. is this correct or did I write down incorrect information??

Jessica Lutz 2E
Posts: 56
Joined: Fri Sep 29, 2017 7:04 am

Re: zero order rate?

This is true! You can see from the equation [A]=-kt+[A]o that the concentration of A changes only as a result of k and time, not because of its own concentration like in the first order equation (that uses ln[A]) or the second order equation (that uses 1/[A]).

Jasmine Botello 2F
Posts: 67
Joined: Fri Sep 29, 2017 7:04 am

Re: zero order rate?

i'm a little confused.. how is [A] different from ln[A] or 1/[A]?

Nina Gautam 1K
Posts: 52
Joined: Fri Sep 29, 2017 7:04 am

Re: zero order rate?

It's not necessarily because the first and second order equations start with ln[A] and 1/[A] instead of just [A], those are just mathematical functions that make it easier to understand the other side of the equation. The rate of reaction in first and second reactions depend on the concentration on initial reaction. However, zero order reactions occur at a rate that is constant throughout the reaction. This can occur if there is a catalyst or enzyme present, for example, which controls the speed of the reaction no matter how much reactant is present.

Posts: 31
Joined: Sat Jul 22, 2017 3:00 am

Re: zero order rate?

That is correct; a zero order reaction rate does not depend on the concentration of the reactant present, as long as there is some reactant. When integrating the rate law, we get Rate = $k[A]^{0} = k$ . Since anything raised to the zero power is 1, we can see that the rate just depends on k.

Jennie Fox 1D
Posts: 66
Joined: Sat Jul 22, 2017 3:01 am

Re: zero order rate?

True, in zero order reactions the rate does not depend on concentration. d[A]=-kdt

Shreya Ramineni 2L
Posts: 50
Joined: Fri Sep 29, 2017 7:07 am

Re: zero order rate?

This is true; rate is independent of concentration, as the differential rate law is rate=k ([A]^0=1).

Caroline LaPlaca
Posts: 30
Joined: Sat Jul 22, 2017 3:01 am

Re: zero order rate?

With a zero order reaction! The rate is independent of the concentration

snehabhargava
Posts: 52
Joined: Thu Jul 13, 2017 3:00 am

Re: zero order rate?

That is definitely correct.

Pooja Nair 1C
Posts: 55
Joined: Thu Jul 13, 2017 3:00 am

Re: zero order rate?

Yup! Zero order rates are independent of concentration, but assumes that there is some reactant.

vaishali 1D
Posts: 61
Joined: Fri Sep 28, 2018 12:19 am

Re: zero order rate?

That's correct! zeroth-order reactions have rates that won't vary when the reactant concentrations change. If the concentrations of reactants change and the rate remains the same, the reaction is zero order.

Chloe Qiao 4C
Posts: 65
Joined: Fri Sep 28, 2018 12:27 am

Re: zero order rate?

It is correct. Zero order reaction usually involves a catalyst or enzyme that works at its maximum potential. Increasing concentration cannot increase the rate the catalyst or enzyme works, and therefore zero order reactions do not depend on the concentration.

805087225
Posts: 30
Joined: Thu Jun 07, 2018 3:00 am

Re: zero order rate?

This is true. For a zero order, Rate = K(conc) raised to power 0. So it is just K.

Calvin Patel 2H
Posts: 37
Joined: Fri Sep 28, 2018 12:22 am

Re: zero order rate?

Yes, it is independent of concentration.

805169754
Posts: 61
Joined: Fri Sep 28, 2018 12:19 am

Re: zero order rate?

You wrote down the correct information. Zero order reactions are not dependent on the concentrations of the reactant