Ranking elements
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Ranking elements
How can you determine the amount of reducing or oxidizing power that an element has compared to other elements so that you can rank them in order of increasing or decreasing power?
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Re: Ranking elements
No, there is not a periodic trend we can rely on for this type of deduction. You need the reduction half reactions to determine which element in a reaction has a greater oxidizing or reducing power.
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Re: Ranking elements
You would look at the standard potential of the reaction. The higher standard potential value, the stronger it is as an oxidizing agent. While, the smaller (or more negative) the standard potential is, the stronger it is as a reducing agent.
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Re: Ranking elements
You could refer to activity series of metals. For example, https://www.thoughtco.com/activity-seri ... als-603960.
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Re: Ranking elements
the more negative the number, the higher reducing potential that element has. You would be given the values and just rank them from that.
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Re: Ranking elements
You would look at standard reduction potentials. the key here is the word reduction, however. you MUST look at reduction potentials, not oxidation potentials, because the signs matter. if you're looking at a reduction potential, the more positive, the more oxidizing power, and the more negative, the more reducing power.
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Re: Ranking elements
Like in the test, you will be given the standard reduction potentials and you must judge from there. For context: The more positive the potential is the more likely it will be reduced.
So using deductive reasoning, the more negative the potential, the less likely it will be reduced (and more likely it will be oxidized).
So using deductive reasoning, the more negative the potential, the less likely it will be reduced (and more likely it will be oxidized).
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Re: Ranking elements
By looking at standard reduction potentials, you can determine the reducing or oxidizing power. The more positive the potential, the greater the electron pulling power of the reduction half-reaction which means it is more likely to be reduced.
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