4.29 Green book

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Parsia Vazirnia 2L
Posts: 44
Joined: Fri Jul 22, 2016 3:00 am

4.29 Green book

Postby Parsia Vazirnia 2L » Sat Mar 04, 2017 8:47 pm

On the bottom of page 85 of the course reader, how do you know that Step 1 is slower and has a higher activation energy than step two? Can someone apply this to 4.29 in the green book? Will the reaction profile always look like this?

William_Lee_Dis_3H
Posts: 15
Joined: Wed Sep 21, 2016 2:57 pm

Re: 4.29 Green book

Postby William_Lee_Dis_3H » Sat Mar 04, 2017 9:08 pm

Ea1>Ea2 because step 1 involves breaking two bonds whereas step 2 is the formation of one bod. Therefore k1<k2

Absolute Zero 1O
Posts: 14
Joined: Wed Sep 21, 2016 2:56 pm

Re: 4.29 Green book

Postby Absolute Zero 1O » Mon Mar 06, 2017 8:44 am

Breaking bonds has higher activation energy than forming bonds. The step with the highest activation energy is the slowest.

melissa carey 1f
Posts: 53
Joined: Fri Sep 29, 2017 7:06 am

Re: 4.29 Green book

Postby melissa carey 1f » Wed Mar 14, 2018 12:43 pm

this can be seen in the arrhenius equation:

https://www.chemguide.co.uk/physical/basicrates/arrhenius.html


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