## delta S for reversible and irreversible reactions

$\Delta S = \frac{q_{rev}}{T}$

Hannah Guo 3D
Posts: 56
Joined: Fri Sep 29, 2017 7:06 am

### delta S for reversible and irreversible reactions

Can someone explain why deltaS(tot, rev)=0, but deltaS(tot, irri)>0 ?

Michaela Capps 1l
Posts: 50
Joined: Thu Jul 27, 2017 3:00 am

### Re: delta S for reversible and irreversible reactions

When it is reversible, the system is at equilibrium so it =0. When deltaS >0 the reaction is spontaneous, which is a part of the second law of thermodynamics