Help on 15.3

[Fenared Ortiz 3K]

In the answers it said that the answer is 2.2x10^-5 mol/(L*s), but I do not understand why they didn't convert the mL to L before solving the problem. Also how do we get those units?

[Leanne Wong 1H]

The answer should be in mmol/Lxs and there's no need to change L. If anything, you should just convert mmol to mol to get the answer in mol/LxS.

[Katie Lam 1B]

Rate is expressed as change in concentration over time, so the units are mol/(L*s).

[Shane Simon 2K]

I believe you meant to type in 15.13 instead of 15.3 for this problem. In the solution manual, the mL value of 750. mL is converted to liters which is just .750 L. The problem converts the grams of H2 given into concentration of H2 by dividing by this .750 L and dividing by the molar mass. The same thing is then done to the mass of I2 given. These concentrations are then multiplied by the k constant that is given in the question to get the answer of 2.2x10^-5 mol/(L*s). The units work like this: (L*mol^-1*sec^-1)*(mol*L^-1*sec^-1)*(mol*L^-1*sec^-1) = mol*L^-1*sec^-1

[Ilan Shavolian 1K]

i think this is just some ambiguity in the solutions manual. the units for k are always mol * L/ s, and they converted to that but just didn't show the work

[Rishi Khettry 1L]

if you convert all given mmol values to mol values and then run the calculation, you should get the correct answer as given in the solutions manual

[Michael Lee 2I]

The units of k are always mol * L/s

[Michael Lee 2I]

The units of k are always mol * L/s