## 15.51

$K = \frac{k_{forward}}{k_{reverse}}$

RenuChepuru1L
Posts: 58
Joined: Thu Jul 27, 2017 3:00 am

### 15.51

Is rate of formation always the concentrations of the reactants of the rate determining step times k. also I didn't get what the solution was saying about second order

Christiana2D
Posts: 23
Joined: Fri Sep 29, 2017 7:06 am

### Re: 15.51

Yes, the rate law is based on the rate determining step/slow step. It's second order because it depends on the concentrations of two different elements ([NO] and [Br2]) making it bimolecular.

Timothy Kim 1B
Posts: 62
Joined: Fri Sep 29, 2017 7:04 am

### Re: 15.51

would the unique rate for the formation of NOBr have a coefficient of 2?