test 2

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904940852
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Joined: Fri Sep 29, 2017 7:07 am

test 2

Postby 904940852 » Sun Mar 18, 2018 2:14 am

what was the answer to question 7 on the test?

Glendy Gonzalez 1A
Posts: 52
Joined: Fri Sep 29, 2017 7:07 am

Re: test 2

Postby Glendy Gonzalez 1A » Sun Mar 18, 2018 9:02 am

The answer should be E=-0.037V

604807557
Posts: 51
Joined: Wed Nov 16, 2016 3:02 am

Re: test 2

Postby 604807557 » Sun Mar 18, 2018 10:34 am

How do you calculate it?

Merzia Subhan 1L
Posts: 33
Joined: Thu Jul 13, 2017 3:00 am

Re: test 2

Postby Merzia Subhan 1L » Sun Mar 18, 2018 10:36 am

you have to use delta G naught = -nFE for each step because you can't just add up the Es. when you get the final delta G, convert it back to E.

Minie 1G
Posts: 63
Joined: Fri Sep 29, 2017 7:04 am

Re: test 2

Postby Minie 1G » Sun Mar 18, 2018 10:39 am

you use the deltaG=-nFE equation.
Fe2+ + e- -> Fe2+ deltaG1 = -(1)(F)(0.77)
Fe2+ + 2e- => Fe(s) deltaG2 = -(2)(F)(-0.44)

Add them up, then solve for E.
deltaG1+deltaG2 = -(3)(F)(E).

Which is -0.037 V.

Megan_Ervin_1F
Posts: 78
Joined: Fri Sep 28, 2018 12:18 am

Re: test 2

Postby Megan_Ervin_1F » Wed Feb 20, 2019 8:15 pm

What sections in the seventh edition will be on the test 2


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